Skip to main content

Circles

Circles and tangents

Question
If from any point on the circle x2 + y2 +2gx + 2fy + c = 0, tangents are drawn to the circle x2 + y2 + 2gx + 2fy + csin2α + (g2 + f2)cos2 α = 0, then angle between the tangents is 

Concepts used
- Circle with equation x2 + y2 + 2gx + 2fy + c = 0, has center at (-g,-f) and radius √(g2+f2-c),
√ (g2+f2-c) 
- sin2 + cos2 = 1

Answer
Rearrange the equation of circles to find the centers and radii
Circle 1 - x2 + y2 +2gx + 2fy + c = 0
x2 + y2 +2gx + 2fy + c = 0
x2 + y2 +2gx + 2fy + g2 + f2 = g2 + f2 - c 
(x+g)2 + (x+f)2 = (√(g2+f2-c))2

Circle 2 - x2 + y2 + 2gx + 2fy + csin2α + (g2 + f2)cos2 α = 0
x2 + y2 + 2gx + 2fy + g2 + f2 = g2 + f2 - csin2α - (g2 + f2)cos2 α 
(x+g)2 + (x+f)2 = (√(g2 + f2 - csin2α - (g2 + f2)cos2 α ))2

We find that the circles share a common center and differ only in their radii.


From the inherent property of tangents Circle 1 is bigger than Circle 2. It is required to find <

Fact:
If two chords intersect in the interior of a circle, then the measure of each angle is one half the sum of themeasures of the arcs intercepted by the angle and its vertical angle.

If a tangent and a secant intersect in the exterior of a circle, then the measure of the angle formed is one half the difference of the measures of the intercepted arcs. 

If two tangents intersect in the exterior of a circle, then the measure of the angle formed is one half the difference of the measures of the intercepted arcs.

If two secants intersect in the exterior of a circle, then the measure of the angle formed is one half the difference of the measures of the intercepted arcs.

Derivation

Popular posts from this blog

ISRO Mechanical Engineering Fluid Mechanics Questions, Answers and Explanation

ISRO Mechanical Engineering Fluid Mechanics Fluid Properties - Bulk modulus 2011. 10.  A liquid compressed in cylinder has a volume of 0.04 m 3  at 50kg/cm 2  and a volume of 0.039 m 3  at 150 kg/cm 2 . The bulk modulus of elasticity of liquid is a) 400 kg/cm 2 b) 40 x 10 6  kg/cm 2 c) 40 x 10 5  kg/cm 2 d) 4000 kg/cm 2 Answer d) 4000 kg/cm 2 Explanation The bulk elastic properties of a material determine how much it will compress under a given amount of external pressure. The ratio of the change in pressure to the fractional volume compression is called the bulk modulus of the material. The reciprocal of the bulk modulus is called the compressibility of the substance. Bulk Modulus, B = ΔP/(ΔV/V) Here ΔP = 150-50 =100 kg/cm 2 ΔV = 0.04-0.039 = 0.001m 3 V = 0.04m 3 B = (100/(0.001/0.04)) = 100x0.04/0.001 =  4000 kg/cm 2 Fluid Properties - Surface Tension 2011.13  If the surface tension of water-air interface ...

ISRO Mechanical Engineering Heat Transfer Questions, Answers and Explanation

ISRO Mechanical Engineering Heat Transfer Questions, Answers and Explanation Conduction 2017.2.62.  The distribution of a temperature T, at a particular instant , across a large concrete wall, 1m thick, which is heated from one side is given by the equation T = 150-80x+16x 2 , where the distance x is in meters and T is in degree Celsius. Thermal conductivity of wall is 0.6W/mK, area of cross section is 10 m 2 . The heat accumulated in unit time at this instant in the concrete wall is a) 768J/sec b) 384J/sec c) 96J/sec d) 192J/sec Answer d) 192J/sec Explanation Heat accumulated = Heat conducted away - Heat conducted in Q = kA*[dT/dx] at x = 1 minus at at x = 0 = 0.6*10*(-80+32x) at x = 1 minus at x = 0 =6*32 = 192J/sec General 2017.2.29.  Which of the following is FALSE? a) Heat flow by conduction is directly proportional to the area and temperature gradient b) Heat flow by convection is directly proportional to the area and temperature differen...

ISRO Mechanical Engineering/Refrigeration and Air Conditioning Thermal Engineering Questions, Answers and Explanation

ISRO Mechanical Engineering Thermal Engineering Questions, Answers and Explanation System Properties 2007.2.  The universal gas constant of a gas is the product of molecular weight of the gas and a) Gas constant b) Specific heat at constant pressure c) Specific heat at constant volume d) None of the above Answer a) Gas constant Explanation The value of universal gas constant is 8.314 J mol -1 K -1 . This when divided by the molecular weight of gas we get specific gas constant Molecular mass of air = 28.97 g/mol R air  = 8.314x1000/28.97 J kg -1 K -1  = 287  J kg -1 K -1 . 2007.3.  Van der Waal's equation of state of a gas is a) pV = nRT b) (p+a/V 2,/sup>)(v+b) = RT c) (p+a/V 2,/sup>)(v-b) = RT d) (p-a/V 2,/sup>)(v-b) = RT Answer c) (p+a/V 2,/sup>)(v-b) = RT Explanation The constant 'a' provides correction for inter molecular forces and b for finite molecular size.  The effect of the finite volume of the particl...