ISRO 2017 December Mechanical Questions, Answers and Explanation
Question Set E
1. The specific metal cutting energy is expressed asa) τ cos(β - α)⁄sin φ cos(φ+β-α)
b) τ sin(β - α)⁄sin φ cos(φ-β+α)
c) τ cos(α - β)⁄sin φ cos(φ-β+α)
d) τ sin(α - β)⁄sin φ cos(φ+β-α)
where α is rake angle, β is friction angle, φ is shear angle and τ is the shear stress.
Answer
a) τ cos(β - α)⁄sin φ cos(φ+β-α)
Explanation [Manufacturing Technology]
Specific metal cutting energy is defined as the energy expended in removing a unit volume of work-piece material.
= Energy/Volume Removed
Energy = Force of cut x velocity of tool
Volume Removed = Velocity of tool x Width of cut x Depth of cut
Specific metal cutting energy = Force of cut/(Width of cut x Depth of cut)
Shear force = shear stress x Area of shear
= τ x width of cut x depth of cut /sin φ
Shear force/Force of cut = cos(φ+β-α)/cos(β - α)
Force of cut = Shear force x cos(β - α)/cos(φ+β-α)
Specific metal cutting energy = Shear force x cos(β - α)/(cos(φ+β-α)x width of cut x depth of cut x sin φ)
= Shear stress x cos(β - α)/(cos(φ+β-α) x sin φ)
= τ cos(β - α)⁄sin φ cos(φ+β-α)
2. For isotropic
materials, the modulus of Elasticity in tension and shear (E and G)
are related to the Poisson's ratio (nu) as follows= Energy/Volume Removed
Energy = Force of cut x velocity of tool
Volume Removed = Velocity of tool x Width of cut x Depth of cut
Specific metal cutting energy = Force of cut/(Width of cut x Depth of cut)
Shear force = shear stress x Area of shear
= τ x width of cut x depth of cut /sin φ
Shear force/Force of cut = cos(φ+β-α)/cos(β - α)
Force of cut = Shear force x cos(β - α)/cos(φ+β-α)
Specific metal cutting energy = Shear force x cos(β - α)/(cos(φ+β-α)x width of cut x depth of cut x sin φ)
= Shear stress x cos(β - α)/(cos(φ+β-α) x sin φ)
= τ cos(β - α)⁄sin φ cos(φ+β-α)
a) E = G/(2(1+ν))
b) G = E/(2(1+ν))
c) G = E/(2(1-ν))
d) E = G/(2(1-ν))
Answer
b) G = E/(2(1+ν))
Explanation [Strength of Materials]
Derivation of relation between Modulus of elasticity in tension and shear
3. Which of the
following is NOT true?
a) For direct impact
of two bodies, coefficient of restitution is the ratio of relative
velocity of approach of the two bodies to their relative velocity of
separation.
b) Conservation of
angular momentum implies that total angular momentum of a system
remains constant unless acted on by an external torque
c) Conservation of
linear momentum in a given direction implies that the sum of external
forces in that direction is zero.
d) The coefficient
of friction is independent of area of contact.
Answer
a) For direct impact of two bodies, coefficient of restitution is the ratio of relative velocity of approach of the two bodies to their relative velocity of separation.
Explanation [Engineering Mechanics]
Actually, for direct impact of two bodies, coefficient of restitution is the ratio of relative velocity of separation to the their relative velocity of approach
4. If f(t) = eat, its Laplace transform (for s > a) is given by
a) a⁄s2 + (s-a)
b) √π⁄2(s-a)
c) 1⁄(s-a)
d) Does not exist
Answer
c) 1⁄(s-a)
Explanation [Engineering Mathematics]
If L{f(t)}=F(s), then L{eatf(t)}=F(s-a)
In the problem f(t) = 1, L(1) = F(s) = 1/s
Therefore, L(eat1) = F(s-a) = 1/(s-a)
5. Smallest thickness which can be measured by a slip gauge is
a) 1.001 mm
b) 0.01 mm
c) 0.001 mm
d) none of these
Answer
a) 1.001 mm
Explanation [Manufacturing Technology]
Slip gauge set of 56 slips is made up as shown below :
9 slips 1.001 to 1.009 in steps of 0.001 mm
9 slips 1.01 to 1.09 in steps of 0.01 mm
9 slips 1.0 to 1.9 in steps of 0.1 mm
25 slips 1 to 25 in steps of 1.0 mm
3 slips 25 to 75 in steps of 25 mm.
From the given choices the smallest thickness that can be measured is 1.001mm and not 0.01mm or 0.001mm.
Answer
a) 1.001 mm
Explanation [Manufacturing Technology]
Slip gauge set of 56 slips is made up as shown below :
9 slips 1.001 to 1.009 in steps of 0.001 mm
9 slips 1.01 to 1.09 in steps of 0.01 mm
9 slips 1.0 to 1.9 in steps of 0.1 mm
25 slips 1 to 25 in steps of 1.0 mm
3 slips 25 to 75 in steps of 25 mm.
From the given choices the smallest thickness that can be measured is 1.001mm and not 0.01mm or 0.001mm.
6. The deflection of
an elastic member at the point of application of a force in the
direction of that force is given by the derivative of member's total
strain energy taken with respect to applied force. This is known as
a) Principle of
conservation of strain energy
b) Castigliano's
theorem
c) Conservation of
momentum
d) Saint-Venant's
Principle
Answer
b) Castigliano's theorem
Explanation [Strength of Materials]
There is no such thing as conservation of strain energy. Strain energy acquired by a structure is acquired by the work done due to deflection.
Castigliano’s first theorem
The first partial derivative of the total internal energy (strain energy) in a structure with respect to any particular deflection component at a point is equal to the force applied at that point and in the direction corresponding to that deflection component.
This first theorem is applicable to linearly or nonlinearly elastic structures in which the temperature is constant and the supports are unyielding.
Castigliano’s second theorem
The first partial derivative of the total internal energy in a structure with respect to the force applied at any point is equal to the deflection at the point of application of that force in the direction of its line of action.
Conservation of momentum does not apply in this case as there is no velocity involved.
Saint-Venant's Principle
If the forces acting on a small portion of the surface of an elastic body are replaced by another statically equivalent system of forces acting on the same portion of the surface, this redistribution of loading produces substantial changes in the stresses locally but has a negligible effect on the stresses at distances which are large in comparison with the linear dimensions of the surface on which the forces are changed.
7. Thumb rule
between feed and nose radius in rough turning is
a) f = 0.3r
b) f = 0.5r
c) f = 0.7r
d) f = 0.9r
Answer
b) f = 0.5r
Explanation [Manufacturing Technology]
Rough turning is the removal of excess stock from a work piece as rapidly and efficiently as possible.
Small nose radius
- Ideal for small cutting depth
- Reduces vibration
- Less insert strength
Large nose radius
- Heavy feed rates
- Large depths of cut
- Strong edge
- Increased radial forces
The radial forces that push the insert away from the cutting surface becomes more axial as the depth of cut increases. It is preferable to have more axial forces instead of radial, which have a negative effects on the cutting action e.g. with more tendencies to vibrate and bad surface finish with increased radial forces.
The nose radius also affects the chip formation. Generally, chip breaking improves with a smaller radius.As a general rule of thumb, the depth of cut should be greater than or equal to 2/3 of the nose radius, or 1/2 of the nose radius in the feed direction.
8. Which of the
following is FALSE?
a) A reverted gear
train is one in which the first and last gears are on the same axis.
b) Train value for a
gear is the ratio of product of driven tooth numbers to product of
driving tooth numbers.
c) A planetary gear
train is one in which the axes of some of the gears may have a
motion.
d) A compound gear
train is one which has two or more gears on each axis.
Answer
b) Train value for a gear is the ratio of product of driven tooth numbers to product of driving tooth numbers.
Explanation [Theory of Machines and Mechanical Vibrations]
By definition the axes of first driver and last driven of a reverted gear is co-axial.
Train value of a gear train is the ratio of the speed of the driven gear to the speed of the driving gear. As the speed of a gear is inversely proportional to the number of teeth in it the correct definition of the train ratio is the "ratio of product of driving tooth numbers to the product of the driven tooth numbers".
In a planetary gear train at-least one of the gears revolve around another gear in the gear train.
A compound gear train is one which at-least one pair of gears are rigidly mounted on the same shaft and thus having same revolution speed.
9. Which of the
following is true for ductile materials?
a) Engineering
stress – strain curve cannot have negative slope
b) Most applicable
failure theory is maximum principal stress theory
c) Ultimate strain
is the strain at ultimate stress
d) Strain hardening
is represented by a negative slope in engineering stress strain curve
Answer
c) Ultimate strain is the strain at ultimate stress
Explanation [Strength of Materials]
Principal stress theory is applicable for brittle materials.
10. Transportation
method is concerned with
a) Value analysis
b) Linear
programming
c) Queuing theory
d) Break-even
analysis
Answer
b) Linear programming
Explanation [Manufacturing Technology]
Answer
b) Linear programming
Explanation [Manufacturing Technology]
Value analysis - the systematic and critical assessment by an organization of every feature of a product to ensure that its cost is no greater than is necessary to carry out its functions.
Linear programming - Linear programming is a method to achieve the best outcome in a mathematical model whose requirements are represented by linear relationships.
Queuing theory - Queuing theory is the mathematical study of waiting lines, or queues. A queuing model is constructed so that queue lengths and waiting time can be predicted.
Break-even analysis - Break-even analysis is a technique widely used by production management and management accountants. ... Total variable and fixed costs are compared with sales revenue in order to determine the level of sales volume, sales value or production at which the business makes neither a profit nor a loss
Transportation method - The Transportation Method of linear programming is applied to the problems related to the study of the efficient transportation routes i.e. how efficiently the product from different sources of production is transported to the different destinations, such as the total transportation cost is minimum.
11.The reaction in
which a liquid phase transform into two different solid phases is
called
a) Eutectoid
reaction
b) Peritectic
reaction
c) Eutectic reaction
d) Peritectoid
reaction
Answer
c) Eutectic reaction
Explanation [Material Science]
Answer
c) Eutectic reaction
Explanation [Material Science]
Eutectoid reaction - This describes the phase transformation of one solid into 2 different solids. In the Fe-C system there is a eutectoid point at approximately 0.8%wt C, 723oC.
Solid γ gives Solid α + Solid β
or Austenite gives Ferrite + Cementite
Peritectic reaction - A peritectic reaction is a reaction where a solid phase and liquid phase will together form a second solid phase at a particular temperature and composition
Eutectic reaction - A eutectic reaction is a three-phase reaction, by which, on cooling, a liquid transforms into two solid phases at the same time.
Peritectoid reaction - A type of isothermal reversible reaction in the solid state that results in a new n-1 solid phase from n phases.
12. Margin wear in
drill is due to
a) abrasion
b) vibration
c) thermal softening
d) diffusion
Answer
c) thermal softening
Explanation [Manufacturing Technology]
The margin edge of a drill contacts the drilled hole surface, therefore its wear has a large impact on the hole quality. The only clear sign of margin wear is revealed by lateral vibration at the final stage of the drilling process.
Thermal softening is a heat treatment process; softening processes remove the lattice defects introduced into the aluminium structure during cold working (such as rolling or cold impact extrusion). This also leads to an increase in ductility. In contrast to soft annealing, thermal softening occurs as a temperature below the recrystallisation temperature.
Work-piece material is subjected to work hardening and thermal softening effect during machining, especially at high cutting temperature and pressure. When machining titanium alloys, the hardness just beneath the machined surface was found to be softer than the bulk material hardness due to the thermal softening effect. However, when the depth below the machined surface increases, the hardness value starts to increase before reaching its peak value and finally drops gradually to the bulk material hardness. The increase in hardness value is directly associated with the effect of work hardening. This effect depends on the temperature, cutting time and the mechanism of internal stress relaxation.
Attrition and diffusion are the dominant tool wear mechanisms, especially in the helical flute of drill. With prolonged drilling, these tool wear mechanisms lead to the catastrophic failure of the drill.
Attrition wear is a removal of grains or agglomerates of tool material by the adherent chip or work-piece. This could be due to intermittent adhesion between the tool and the work-piece as a result of the irregular chip flow and the breaking of a partially stable built-up edge. When seizure between the tool and the work-piece is broken, small fragments of the tool can be plucked out due to weakening of the binder and transported material via the underside of the chip or by the work-piece. The presence of fatigue during machining operation can initiate cracks and also encourage cracks propagation on the tool.
Diffusion wear is associated with the chemical affinity between the tool and work-piece materials under high temperature and pressure during machining of titanium alloys. An intimate contact between the tool work piece interface at temperature above 800º C provides an ideal environment for diffusion of tool material across the tool-work-piece interface. Due to high chemical reactivity of titanium alloys, carbon reacts readily with titanium. Therefore, the formation of titanium carbide occurs at the interface between the tool and work material.
13. The specific
speed of the Kaplan turbine is
a) 2.0-5.0
b) < 0.3<0 .3="" 0="" p="">0>
c) 0.3-2.0
d) none of these
Answer
a) 2.0-5.0
Explanation [Fluid Mechanics]
Dimensionless specific speed range
Pelton wheel - 0.03 to 0.3
Francis turbine - 0.3 to 2
Kaplan turbine - 2 to 5
14. The type of
locator used to prevent jamming during locating of a work piece is
a) concentric
locator
b) integral locator
c) equilateral
locator
d) spherical locator
Answer
d) spherical locator
Explanation
Concentric locators, for the most part, locate a work-piece from a central axis. This axis may or may not be in the center of the work-piece.
15. A carton
carrying vessel of mass 10 tons (width = length = 5m, height = 6m),
floats on water. The mass of contents of the vessel are symmetrically
placed. If the vessel tilts by 0.01 radians by moving a 50kg carton
from the centre by a distance of 2m towards side in horizontal
direction, the metacentric height of the vessel is (g = 10m/s2)
a) 1m
b) 3m
c) 1.5m
d) 2m
Answer
a) 1m
17. Which if the
following is TRUE for vibration of a mechanical system
a) Damping ratio is
the ratio of the critical damping to the actual damping
b) The damping can
be obtained from the response of the system under forced vibration
using logarithmic decrement method.
c) For damped
mechanical systems, the amplitude of vibration tends to become
infinity when excitation frequency reaches the system's natural
frequency
d) Amplitude ratio and transmissibility of a vibration isolator is unity when the
frequency of exciting force is sqrt(2) times the natural frequency.
Answer
d)
18. What is the
maximum rate that a heat pump which uses 1kW of electric power can
supply heat to a house at 27C when the outside temperature is 12C
a) 50J/s
b) 25kJ/s
c) 20kJ/s
d) 30J/s
Answer
c) 20kJ/s
Explanation [Thermal Engineering]
At maximum efficiency, Q2/Q1 = T2/T1
Q2/Q1 = T2/T1=300/285, Q1=285Q2/300
Q1+W=Q2
W = 15/300 Q2
Q2 = 20*1kJ/s = 20kJ/s
20. White iron
structure consists of
a) Pearlite
b) Cementite
c) Ferrite
d) Pearlite and
Cementite
23. A man draws 3
balls from a jug containing 5 white balls and 7 black balls. He gets
Rs. 20 for each white ball and Rs. 10 for each black ball. What is
his expectation?
a) Rs. 21.25
b) Rs 42.50
c) Rs 31.50
d) Rs 45.21
Answer
b) Rs 42.50
Explanation [Engineering Mathematics]
3 balls can be drawn in the following ways
- 3 white balls, P = 5C3/11C3 = 10/220 = 2/44
- 2 white balls and 1 black ball, P = 5C2*7C1/11C3 = 70/220 = 14/44
- 1 white ball and 2 black balls, P = 5C1*7C2/11C3 = 125/220 = 21/44
- 3 black balls, P = 7C3/11C3 = 35/220 = 7/44
Expectation = sum of the product of probability and the money he gets for each combination
= (2/44)*60 + (14/44)*50 + (21/44)*40 + (7/44)*30 = 935/22 = 85/2 = 42.50
27. Arrange the
metals Aluminium, Copper, Iron & Silver in increasing order of
thermal conductivity
a) Iron, Aluminium,
Copper, Silver
b) Aluminium, Iron,
Copper, Silver
c) Copper, Iron,
Silver, Aluminium
d) Iron, Copper,
Aluminium, Silver
Answer
a) Iron Aluminium, Copper, Silver
Explanation [Material Science]
Thermal conductivity of Silver - 406 W/mK
Thermal conductivity of Copper - 385 W/mK
Thermal conductivity of Aluminium - 205 W/mK
Thermal conductivity of Iron - 79.5 W/mK
29. Which of the
following is FALSE?
a) Heat flow by
conduction is directly proportional to the area and temperature
gradient
b) Heat flow by
convection is directly proportional to the area and temperature
difference
c) Heat flow by
radiation is directly proportional to the cube of absolute temperature
of the radiating body
d) Emissivity of
perfect black body is unity
Answer
c)
Explanation [Heat Transfer]
Heat flow by radiation is directly proportional to the fourth power of absolute temperature of the radiating body.
30. The most
applicable failure theory for metals like Aluminium is
a) Maximum principal
stress theory
b) Maximum principal
strain theory
c) Total strain
energy theory
d) Maximum
distortion energy theory
Answer
d) Maximum distortion energy theory
31. Which one of the
following is FALSE?
a) Number of Taps
generally used for hand tapping is 3
b) Piispanen's model
in machining is used to estimate shear strain
c) Chip hammering
during machining is due to improper chip control
d) Cemented carbide
tools are generally poor in compression
Answer
d)
32. A statistical
process control chart which shows the number of defects found in a
subgroup of fixed size is
a) C-chart
b) R-chart
c) Control chart
d) Gantt chart
Answer
a) C-chart
33. Complex
irregular three dimensional surfaces can be located using the
following method
a) Sighting
b) Nesting
c) Integral locators
d) Buttons
Answer
b) Nesting
36. A point P moves along the path y = x2 -4. What is the displacement when the point moves from x =1 to x = 3.
a) 8.24, @ tan-1 (4)
b) 2, @ tan-1 (1)
c) 11.3, @ tan-1 (4)
d) 11.3, @ tan-1 (1)
Answer
a) 8.24, @ tan-1 (4)
Explanation [Engineering Mathematics]
when x = 1, y = 1-4 = -3
when x = 3, y = 9-4 = 5
distance between the 2 points = √ (22+82) = √ (68), which is just greater than 8. So other options are eliminated.
38. Identify the
geometric characteristic that describe the feature geometry and the
inter-relationship of part features
a) form tolerance
b) form
c) orientation
tolerance
d) dimension
Answer
b) form
39. Isothermal compressibility of an ideal gas is
a) nR/VP
b) nRT/VP2
c) nR/VP2
d) nRT/VP
Answer
b) nRT/VP2
Explanation [Thermal Engineering]
Compressibility is the inverse of bulk modulus
Bulk modulus is the ratio change in pressure to strain = -dP/(dV/V)
Therefore, compressibility = -dV/(VdP)
For an ideal gas PV = nRT
Since the process is isothermal dT = 0, only differentiable variables are P and V
V = nRT/P
Differentiating dV = -nRTdP/P2
Compressibility = -dV/(VdP) = nRT/VP2
40. Datum features on the part are
a) permanent
b) temporary
c) either permanent
or temporary
d) none of these
Answer
c) either permanent or temporary
43. Efficiency of
gas turbines lies between
a) 85 to 95%
b) 50 to 60%
c) 30 to 50%
d) 15 to 18%
Answer
d) 15 to 18%
44. Which of the
following is impulse turbine?
a) Francis turbine
b) Kaplan turbine
c) Pelton turbine
d) none of these
Answer
c) Pelton turbine
Explanation [Fluid Mechanics]
Impulse Turbine - The whole pressure energy is transformed to kinetic energy. Eg. Pelton turbine
Reaction Turbine - All pressure energy is not transformed into kinetic energy. Eg. Francis, Kaplan turbine
Answer
c) Pelton turbine
Explanation [Fluid Mechanics]
Impulse Turbine - The whole pressure energy is transformed to kinetic energy. Eg. Pelton turbine
Reaction Turbine - All pressure energy is not transformed into kinetic energy. Eg. Francis, Kaplan turbine
45. Which of the
following is FALSE for bolted joints?
a) Bolted joints are
preloaded to avoid vibration loosening
b) Threads made by
thread rolling process are preferred over machined threads in bolts
c) When external
load is applied to preloaded bolt joint, a bigger percentage of that
load relieves compression of flanges and remaining percentage
increases tension in bolts
d) Bolted joints are
designed such that bolt stiffness is higher than flange stiffness
Answer
d)
46. Root opening of
a Single Vee groove weld joint of plate thickness “t” is
a) t/3
b) t/4
c) t/5
d) t/6
Answer
b) t/4
47. A cubic B-spline
curve requires minimum ......... control points
a) 3
b) 4
c) 5
d) 6
Answer
b) 4
Explanation [Engineering Mathematics]
A line (linear curve) requires minimum 2 control points
A quadratic curve requires minimum 3 control points
In general a curve of degree n requires minimum n+1 control points
48. Which one of the
following is FALSE about Boronizing process?
a) it is a pack
cementation process
b) it can be done
only on high carbon steels
c) it is used to
obtain extremely high wear resistant surfaces on steels
d) it leads to high
distortion
Answer
b)
Answer
b)
49. In dynamic
balancing of machines, which of the following is NOT a method of
measuring the magnitude and location of correction weight for a two
plane correction?
a) Pivoted cradle
method
b) Mechanical
compensation method
c) Pivoted
compensation method
d) Nodal point
method
Answer
c)
51. The critical pressure ratio for maximum discharge in steam nozzle is
a) 2⁄γ+1
b) (2⁄(γ+1))γ
c) (2/(γ+1))γ-1
d) (2/(γ+1))γ/(γ-1)
Answer
d) (2/(γ+1))γ/(γ-1)
Explanation [Thermal Engineering]
Derivation of critical pressure ratio for maximum discharge
52. A jet engine
consumes 1kg of fuel for each 40kg of air intake. Fuel consumption is
1kg/sec. When aircraft travels in still air at 200m/sec, velocity of
discharge of gases with respect to engine is 700m/sec. The power
developed by engine is
a) 7200kW
b) 5600kW
c) 2070kW
d)4140kW
Answer
d) 4140kW
Explanation [Thermal Engineering]
Power developed = Thrust* velocity
A jet engine derives its thrust from compressing incoming air and then mix it with fuel to burn it and then exhausting the hot gases at high velocities through a nozzle.
Thrust = Rate of change of momentum of incoming gases and exhaust gases
Inlet momentum = 40*200 kgm/s
Outlet momentum = (40+1)*700 kgm/s
Power developed = (41*700 - 40*200)*200 = 4140kW
53. Which of the
following is most appropriate for various power cycles?
a) In Carnot cycle,
expansion of vapour occurs without change in entropy
b) In Rankine cycle,
transformation of liquid water in steam generator occurs at constant
temperature
c) In Carnot cycle,
heating of vapor occurs at constant volume
d) In Rankine cycle,
entropy of vapor increases during its expansion in steam turbine
Answer
a) In Carnot cycle, expansion of vapour occurs without change in entropy
Explanation [Thermal Engineering]
Carnot cycle
1. Isothermal compression
2. Isentropic compression
3. Isothermal expansion
4. Isentropic expansion
1 and 2 rules out choice c)
Rankine cycle
1. Isentropic compression
2. Constant pressure heat addition (choice b) ruled out)
3. Isentropic expansion (choice d) ruled out)
4. Constant pressure heat rejection
Answer
a) In Carnot cycle, expansion of vapour occurs without change in entropy
Explanation [Thermal Engineering]
Carnot cycle
1. Isothermal compression
2. Isentropic compression
3. Isothermal expansion
4. Isentropic expansion
1 and 2 rules out choice c)
Rankine cycle
1. Isentropic compression
2. Constant pressure heat addition (choice b) ruled out)
3. Isentropic expansion (choice d) ruled out)
4. Constant pressure heat rejection
55. The reheat
factor Rf for a steam turbine is usually in the range of
a) 0 to 1
b) 1 to 1.065
c) 2 to 2.065
d) 5 to 10
Answer
b) 1 to 1.065
Explanation [Thermal Engineering]
Reheat factor is the ratio of cumulative heat drop to direct isentropic or Rankine heat drop. It is always greater than 1.
Answer
b) 1 to 1.065
Explanation [Thermal Engineering]
Reheat factor is the ratio of cumulative heat drop to direct isentropic or Rankine heat drop. It is always greater than 1.
57. In tolerancing
of a part, unless otherwise specified, individual features of size
must
a) not violate size
limits of MMC at any cross section
b) not violate an
envelope of perfect form at LMC
c) not violate an
envelope of perfect form at MMC
d) none of these
Answer
c)
59. In CAD, the
geometric transformation is expressed as P* = [T]P where T is
transformation matrix. If the matrix T is diagonal, then the
transformation is called
a) translation
b) reflection
c) rotation
d) scaling
Answer
d) scaling
Explanation
Consider T as 2*2 diagonal matrix with diagonal elements a,b
Let P = [[u,v],[y,z]]
P* = [[au,bv],[ay,bz]] which implies P has scaled
60. A water tank is
located 3m above ground and depth of water in tank is 2m. Exit pipe
is 50mm in dia and 50 m long. Velocity of water at the exit at the
ground level is approximately (Take friction factor f = 0.05, g =
10m/s^2)
a) 1.5m/s
b) 2m/s
c) 0.7m/s
d) 1/4 m/s
Answer
c) 0.7m/s
61. The work ratio
of a gas turbine is a function of
a) temperature ratio
and pressure ratio
b) pressure ratio
c) temperature ratio
d) none of these
Answer
a) temperature ratio and pressure ratio
62. The distribution
of a temperature T, at a particular instant , across a large concrete
wall, 1m thick, which is heated from one side is given by the
equation T = 150-80x+16x2, where the distance x is in meters and T
is in degree Celsius. Thermal conductivity of wall is 0.6W/mK, area
of cross section is 10 m2. The heat accumulated in unit time at this
instant in the concrete wall is
a) 768J/sec
b) 384J/sec
c) 96J/sec
d) 192J/sec
Answer
d) 192J/sec
Explanation [Heat Transfer]
Heat accumulated = Heat conducted away - Heat conducted in
Q = kA*[dT/dx] at x = 1 minus at at x = 0
= 0.6*10*(-80+32x) at x = 1 minus at x = 0
=6*32 = 192J/sec
Answer
d) 192J/sec
Explanation [Heat Transfer]
Heat accumulated = Heat conducted away - Heat conducted in
Q = kA*[dT/dx] at x = 1 minus at at x = 0
= 0.6*10*(-80+32x) at x = 1 minus at x = 0
=6*32 = 192J/sec
63. Which of the
following is the permanent mould casting process?
a) Investment
casting process
b) Full mould
process
c) Vacuum casting
process
d) Die casting
process
Answer
d) Die casting process
64. Tolerances
generally followed for tooling design are
a) 5-10% of work
piece tolerance
b) 11-30% of work
piece tolerance
c) 31-50% of work
piece tolerance
d) none of these
65. Which of the
following is FALSE about Normal distribution
a) Normal
Distribution is applied for discrete Random Distribution
b) The shape of the
Normal Curve is Bell Shaped
c) The area under a
standard normal curve is 1
d) The standard
normal curve is symmetric about the value 0
Answer
a)
Explanation
The normal distribution is a commonly encountered continuous probability distribution.
Normal curve is also called "Bell Curve" as it is Bell Shaped.
Area under the standard normal curve is 1.
The standard normal curve is symmetric about the value 0.
Answer
a)
Explanation
The normal distribution is a commonly encountered continuous probability distribution.
Normal curve is also called "Bell Curve" as it is Bell Shaped.
Area under the standard normal curve is 1.
The standard normal curve is symmetric about the value 0.
66. The temperature
of the products of combustion when the maximum amount of chemical
energy is converted to thermal energy is
a) Higher than
adiabatic flame temperature
b) Lower than
adiabatic flame temperature
c) Equal to
adiabatic flame temperature
d) Independent of
adiabatic flame temperature
Answer
c) Equal to adiabatic flame temperature
Explanation [Thermal Engineering]
Maximum amount of chemical energy is converted to thermal energy when the air fuel ratio is stoichiometric. At that ratio, the adiabatic flame temperature is equal to the temperature of the products of combustion.
When the air fuel ratio is less or more the temperature of products of combustion is always less than the adiabatic flame temperature.
When the air fuel ratio is less or more the temperature of products of combustion is always less than the adiabatic flame temperature.
67. Frederic W
Taylor introduced a system of working known as
a) line organisation
b) effective
organisation
c) functional
organisation
d) none of the above
Answer
c) functional organisation
Answer
c) functional organisation
68. Adaptive
response rate forecasting is related to
a) Production
Planning
b) Production
Scheduling
c) Value analysis
d) Inventory control
Answer
d) Inventory control
Answer
d) Inventory control
69. Process in which
lowest tolerances in cast products of ferrous and non ferrous metals
can be achieved is
a) Die casting
b) Shell casting
c) Investment
casting
d) Sand casting
Answer
c) Investment casting
Answer
c) Investment casting
70. Pickling
treatment is cleaning the casting with
a) Soda ash
b) Dilute acid
c) Compressed air
and sand particles
d) Iron shots
Answer
b) Dilute acid
Other Manufacturing Technology Questions
Explanation
Pickling is removal of scale by chemical means.
71. Element which
makes steel stainless
a) Mg
b) Ni
c) C
d) Cr
Answer
d) Cr
Explanation [Material Science]
Chromium is the dominant other metal present in stainless steel (> 10%). It helps forming a very thin stable film of its oxide and hydroxide which limits additional corrosion and is not visible contrary to Iron oxides and hydroxides.
Nickel - Increases strength and hardness without sacrificing ductility and toughness. It also increases resistance to corrosion and scaling at elevated temperatures when introduced in suitable quantities in high-chromium (stainless) steels.
Carbon - The most important constituent of steel. It raises tensile strength, hardness, and resistance to wear and abrasion. It lowers ductility, toughness and machinability.
Magnesium - Magnesium is not used in stainless steel. Magnesium - iron alloys are used to make electrochemical heat sources.
72. Isentropic
process is related to
a) Adiabatic
Expansion
b) Reversible
Adiabatic Expansion
c) Isothermal
Expansion
d) Reversible
Isothermal Expansion
Answer
b) Reversible Adiabatic Expansion
Explanation [Thermal Engineering]
Irreversible free expansion of a gas in adiabatic condition is not isentropic. There is an increase of entropy. The equation of dS=dQ/T is not an accurate equation, the actual equation should be dS=dQreversible/T. For dQ of irreversible the equation should be changed into the clausius inequality form which is dS> dQ irreversibl/T. Under this clausius inequality equation, even dQ is zero in the adiabatic condition, and the right hand side equation is equal to zero, the left side dS is greater than zero which means that the dS entropy is increasing.
An isentropic process is an idealized thermodynamic process that is both adiabatic and reversible. The work transfers of the system are frictionless, and there is no transfer of heat or matter.
In reversible isothermal process the entropy change of the universe is zero. But as temperature of the system remains constant, there is net heat flow into the system thereby increasing the entropy of the system.
In an isothermal expansion there is net increase in entropy as explained before because entropy is a state property
74. Isochoric
changes in ideal gas are characterized by
a) V/T = Const
b) PV = Const
c) P/T = Const
d) None of these
Answer
c) P/T = Const
Explanation [Thermal Engineering]
For an isochoric process volume remains constant, therefore PV = nRT reduces to P/T = constant
75. A cantilever
beam of cross section area 'A', moment of Inertia 'I' and length 'L'
is having natural frequency ω1. If the beam is accidentally broken into
two halves, the natural frequency of the remaining cantilever beam ω2 will be such that
a) ω2
Answer
b) ω2> ω1
Explanation [Theory of Machines and Mechanical Vibrations]
The natural frequency ωn ∝ 1/L2 √ (EI/ρA)
So when the length is halved the natural frequency quadruples.
Answer
a) 10mm
Explanation [Strength of Materials]
From the torsion theory
T/Ip = τ/r
and
P = 2πNT/60
where
T - Torque
Ip - polar moment of inertia = π d4/32
τ - shear stress
r - radius where shear stress is measured
P - power transmitted
N - revolutions per minute
Maximum shear stress occurs at r = d/2
Combining the 2 equations
P = 2πN/60 *2 Ipτ/d
P = πNπ d4τ/(15*32d)
d3 = 15*32*P/(π2Nτ)
= 15*32*7500/(10*3600*100*106)
= 0.000001
d = 0.01m = 10mm
Answer
c) Buckling stress of the structure.
Explanation [Strength of Materials]
Yield strength is the point where the material tends to deform. For the structures that should not deform on usage, the design is based on yield strength of material.
Brittle materials generally fails at the ultimate strength of material.
Buckling under axial compression is normally the controlling design consideration for thin cylindrical structures. Thin and long cylindrical structures fail before the yield strength of the member is reached.
Shear strength of a component is important for designing the dimensions and materials to be used for the manufacture or construction of the component e.g. beams, plates, or bolts
80. A point moves according to the relation x = 8t2 cos ω t , y = -4t3 sin ωt, where x and y are in meters and t in seconds. If angular velocity ω = 8 π rad/s, velocity vector of the point at t = 0.5s is given by
a) 8 + j4π
b) 6 + j20π
c) 8 - j4π
d) -20π -j6
Answer
c) 8 - j4π
Explanation [Engineering Mathematics]
x = 8t2 cos ω t
y = -4t3 sin ωt
u = dx/dt = 16t cos ω t - 8ωt2 sin ω t
v = dy/dt = -12t2 sin ωt - -4ωt3 cos ωt
velocity vector = u + jv
Further Reading
b) ω2> ω1
c) ω2=ω1
d) Cannot be
obtained from the given data
Answer
b) ω2> ω1
Explanation [Theory of Machines and Mechanical Vibrations]
The natural frequency ωn ∝ 1/L2 √ (EI/ρA)
So when the length is halved the natural frequency quadruples.
76. A 3m long steel
shaft has to transmit 7.5kW at 3600rpm. Required shaft diameter is
given by(Take allowable shear stress = 100N/mm2, π2 = 10)?
a) 10mm
b) 7.5mm
c) 25mm
d) 12.5mm
Answer
a) 10mm
Explanation [Strength of Materials]
From the torsion theory
T/Ip = τ/r
and
P = 2πNT/60
where
T - Torque
Ip - polar moment of inertia = π d4/32
τ - shear stress
r - radius where shear stress is measured
P - power transmitted
N - revolutions per minute
Maximum shear stress occurs at r = d/2
Combining the 2 equations
P = 2πN/60 *2 Ipτ/d
P = πNπ d4τ/(15*32d)
d3 = 15*32*P/(π2Nτ)
= 15*32*7500/(10*3600*100*106)
= 0.000001
d = 0.01m = 10mm
77. For thin
cylindrical shell structures loaded in compression, the design is
based on
a) Yield strength of
material
b) Ultimate strength
of material
c) Buckling strength
of the structure
d) Shear strength of
the structure
c) Buckling stress of the structure.
Explanation [Strength of Materials]
Yield strength is the point where the material tends to deform. For the structures that should not deform on usage, the design is based on yield strength of material.
Brittle materials generally fails at the ultimate strength of material.
Buckling under axial compression is normally the controlling design consideration for thin cylindrical structures. Thin and long cylindrical structures fail before the yield strength of the member is reached.
Shear strength of a component is important for designing the dimensions and materials to be used for the manufacture or construction of the component e.g. beams, plates, or bolts
80. A point moves according to the relation x = 8t2 cos ω t , y = -4t3 sin ωt, where x and y are in meters and t in seconds. If angular velocity ω = 8 π rad/s, velocity vector of the point at t = 0.5s is given by
a) 8 + j4π
b) 6 + j20π
c) 8 - j4π
d) -20π -j6
Answer
c) 8 - j4π
Explanation [Engineering Mathematics]
x = 8t2 cos ω t
y = -4t3 sin ωt
u = dx/dt = 16t cos ω t - 8ωt2 sin ω t
v = dy/dt = -12t2 sin ωt - -4ωt3 cos ωt
velocity vector = u + jv
= 16t cos ω t - 8ωt2 sin ω t + j(-12t2 sin ωt - 4ωt3 cos ωt)
Substituting ω = 8 π rad/s and t = 0.5s,
velocity vector = 16*0.5 cos 8 π *0.5 - 8*8 π*0.52 sin 8 π *0.5 + j(-12*0.52 sin 8 π*0.5 -4*8 π*0.53 cos 8 π*0.5)
Substituting ω = 8 π rad/s and t = 0.5s,
velocity vector = 16*0.5 cos 8 π *0.5 - 8*8 π*0.52 sin 8 π *0.5 + j(-12*0.52 sin 8 π*0.5 -4*8 π*0.53 cos 8 π*0.5)
= 8 cos 4 π - 2 sin 4 π + j(-3 sin 4 π -4 πcos 4 π)
= 8 - j4 π
Further Reading
- ISRO 2017 May Mechanical Questions, Answers and Explanation
- ISRO Previous Years (2007 to 2016) Mechanical Questions, Answers and Explanation
- ISRO 2006 Mechanical Questions, Answers and Explanation
- ISRO Mechanical - Engineering Mathematics Questions, Answers and Explanation,
- ISRO Mechanical Manufacturing Technology Questions, Answers and Explanation